5t^2+10t+5=0

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Solution for 5t^2+10t+5=0 equation:



5t^2+10t+5=0
a = 5; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-10}{10}=-1$

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